• TechieDamien@lemmy.ml
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        10 days ago

        Don’t know why you are being down voted. You are correct. There is a difference between a square root and the solutions of x2 = n.

        • Acters@lemmy.world
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          10 days ago

          Yeah, square root implies absolute numbers. You need to manually multiply by -1 to get the other solution to x^2

        • CommanderCloon@lemmy.ml
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          10 days ago

          No?

          In mathematics, a square root of a number x is a number y such that y² = x; in other words, a number y whose square (the result of multiplying the number by itself, or y ⋅ y) is x. For example, 4 and −4 are square roots of 16 because 4² = ( − 4 )² = 16.

          Wikipedia

          • Opisek@lemmy.world
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            10 days ago

            So close yet so far. If only you had read ONE more paragraph.

            Every nonnegative real number x has a unique nonnegative square root, called the principal square root or simply the square root (with a definite article, see below), which is denoted by √x where the symbol “√” is called the radical sign or radix.

            • CommanderCloon@lemmy.ml
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              8 days ago

              This sentence made no sense to me as it directly contradicted the previous one. But it’s just a confusion on my part between the function called square root, which confusingly outputs two different numbers called “square roots”, and “the” number called square root; I’ve edited my comment. Thanks for correcting me!

              • Opisek@lemmy.world
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                8 days ago

                Yeah, I see how that can happen. Very confusing to have the same name for two things differentiated only by the use of a definite or indefinite article.

          • wdx@feddit.org
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            9 days ago

            Look at the inverse of the square root function, f(x)=x² (https://www.desmos.com/calculator/2v5gzbhru8)

            You can get the sqrt of a given y by looking at the x axis. E.g. the value of y=4 has two solutions, x=2 and x=-2. This however does not mean that the sqrt of -4 is also 2! If you look at graph you can see that there are no solutions for y less than 0.

            sqrt(-1) , sqrt(-2) (i ill omit imaginary numbers here) and so on do not have a solution. There is nothing you can replace with such that x × x is < 0 because multiplying two negatives always nets a positive.