I don’t think 10000 year is a problem. There is a real “year 2038 problem” that affects system storing unix time in signed int32, but it’s mostly solved already. The next problem will be in year 33000 or something like that.
Unix computers store time in seconds that have passed since january first 1970. one there have been too many seconds since 1970, it starts breaking. ‘signed’ is a way to store negative numbers in binary. the basics of it are: when the leftmost bit is a 1, it’s a negative number (and then you do some other things to the rest of the number so that it acts like a negative number) so when there have been 09999999 seconds since 1970, if there’s one more second it’ll be 10000000, which a computer sees as -9999999.
A common method of storing dates is the number of seconds since midnight on Jan 1, 1970 (which was somewhat arbitrarily chosen).
A 32-bit signed integer means it can store numbers between 231 through 231 - 1 (subtracting one comes from zero being effectively a positive number for these purposes). 231 - 1 seconds added to Jan 1, 1970 gets you to Jan 19, 2038.
The solution is to jump to 64-bit integers, but as with Y2K, there’s a lot of old systems that need to be updated to 64-bit integers (and no, they don’t necessarily have to have 64-bit CPUs to make that work). For the most part, this has been done already. That would put the date out to 292,277,026,596 CE. Which is orders of magnitude past the time for the sun to turn into a red giant.
I wished I believe this. Or I guess I agree that it is solved in most software but there is lots of commonly used software where it isn’t. One broken bit of software can fairly easily take down a whole site or OS.
Try to create an event in 2040 in your favourite calendar. There is a decent chance it isn’t supported. I would say most calendar servers support it, but the frontends often don’t or vice-versa.
Well, I looked at a Year 10000 problem less than 2 hours ago. We’re parsing logs to extract the timestamp and for that, we’re using a regex which starts with:
\d{4}-\d{2}-\d{2}
So, we assume there to be 4 digits for the year, always. Can’t use it, if you live in the year 10000 and beyond, nor in the year 999 and before.
Do you think so? Surely, it’s able to handle dates before the year 999 correctly, so I’d also expect it to handle years beyond 10000. The \d{4} is just our bodged assumption, because well, I have actually never seen a log line with a year that wasn’t 4 digits…
Each date and time value has a fixed number of digits that must be padded with leading zeros.
To represent years before 0000 or after 9999, the standard also permits the expansion of the year representation but only by prior agreement between the sender and the receiver.[21] An expanded year representation [±YYYYY] must have an agreed-upon number of extra year digits beyond the four-digit minimum, and it must be prefixed with a + or − sign[22] instead of the more common AD/BC (or CE/BCE) notation; by convention 1 BC is labelled +0000, 2 BC is labeled −0001, and so on.[23]
Oh wow, I really expected the standard to just say that however many digits you need are fine, because you know, maths. But I guess, this simplifies handling all kinds of edge cases in the roughly 7975 years we’ve still got.
Yes, there are random systems using every kind of smart or brain-dead option out there.
But the 2038 problem impacts the previous standard, and the current one will take ages to fail. (No, it’s not 33000, unless you are using some variant of the standard that counts nanoseconds instead of seconds. Those usually have more bits nowadays, but some odd older systems do it on the same 64 bits from the standard.)
I don’t think 10000 year is a problem. There is a real “year 2038 problem” that affects system storing unix time in signed int32, but it’s mostly solved already. The next problem will be in year 33000 or something like that.
Is there an ELI5?
Unix computers store time in seconds that have passed since january first 1970. one there have been too many seconds since 1970, it starts breaking. ‘signed’ is a way to store negative numbers in binary. the basics of it are: when the leftmost bit is a 1, it’s a negative number (and then you do some other things to the rest of the number so that it acts like a negative number) so when there have been 09999999 seconds since 1970, if there’s one more second it’ll be 10000000, which a computer sees as -9999999.
A common method of storing dates is the number of seconds since midnight on Jan 1, 1970 (which was somewhat arbitrarily chosen).
A 32-bit signed integer means it can store numbers between 231 through 231 - 1 (subtracting one comes from zero being effectively a positive number for these purposes). 231 - 1 seconds added to Jan 1, 1970 gets you to Jan 19, 2038.
The solution is to jump to 64-bit integers, but as with Y2K, there’s a lot of old systems that need to be updated to 64-bit integers (and no, they don’t necessarily have to have 64-bit CPUs to make that work). For the most part, this has been done already. That would put the date out to 292,277,026,596 CE. Which is orders of magnitude past the time for the sun to turn into a red giant.
I wished I believe this. Or I guess I agree that it is solved in most software but there is lots of commonly used software where it isn’t. One broken bit of software can fairly easily take down a whole site or OS.
Try to create an event in 2040 in your favourite calendar. There is a decent chance it isn’t supported. I would say most calendar servers support it, but the frontends often don’t or vice-versa.
Well, I looked at a Year 10000 problem less than 2 hours ago. We’re parsing logs to extract the timestamp and for that, we’re using a regex which starts with:
So, we assume there to be 4 digits for the year, always. Can’t use it, if you live in the year 10000 and beyond, nor in the year 999 and before.
Just start over at year 0000 AT (after ten thousand)
The ISO time standard will certainly need to be redone
Do you think so? Surely, it’s able to handle dates before the year 999 correctly, so I’d also expect it to handle years beyond 10000. The
\d{4}is just our bodged assumption, because well, I have actually never seen a log line with a year that wasn’t 4 digits…Kinda?
Oh wow, I really expected the standard to just say that however many digits you need are fine, because you know, maths. But I guess, this simplifies handling all kinds of edge cases in the roughly 7975 years we’ve still got.
deleted by creator
There are so many problems there is an entire Wikipedia page dedicated to them.
Yes, there are random systems using every kind of smart or brain-dead option out there.
But the 2038 problem impacts the previous standard, and the current one will take ages to fail. (No, it’s not 33000, unless you are using some variant of the standard that counts nanoseconds instead of seconds. Those usually have more bits nowadays, but some odd older systems do it on the same 64 bits from the standard.)
I’m pretty certain most of my work inevitably ends up being related to a time issue
It’s a UX problem rather than a date format problem at that point. Many form fields require exactly 4 digits.
It’s going to be significantly more than the year 33000 before we run out of 64-bit epoch timestamps.
The max value for signed 64-but epoch values is more than 292 billion years away, or 20 times the age of the universe itself.
So yeah, we’re basically solid forever with 64-bit
33,000 would come from other programs that store the year as a 16-bit signed int. Year 32,768, to be precise.
Luckily I’ll be retired by then.